(-0.2X^(2)+240x)=0

Solution for (-0.2X^(2)+240x)=0 equation:

(-0.2X^(2)+240X)=0

We get rid of parentheses

-0.2X^2+240X=0

a = -0.2; b = 240; c = 0;
Δ = b2-4ac
Δ = 2402-4·(-0.2)·0
Δ = 57600
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{57600}=240$
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(240)-240}{2*-0.2}=\frac{-480}{-0.4}
=+1200
$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(240)+240}{2*-0.2}=\frac{0}{-0.4}
=0
$